change it into cartesian form `(cos(3 pi/4)-i sin(3 pi/4))`

cos((3pi)/4+x)-sin(pi/4-x)=?

cos(pi/4-A)-sin(pi/4+A)=0

z=(1-i)/(cos(pi/3)+i sin(pi/3))

sin^(-1)(cos((3 pi)/(4)))

.Convert polar co-ordinate into cartesian co-ordinates. (2,(3 pi)/(4)), (ii) (1,(pi)/(2)

If z=cos((pi)/(4))+i sin((pi)/(6)), then

sin {cos ((cos ^ (- 1) (3 pi)) / (4))}

If the polar form of a complex number is sqrt(2)(cos(-(3 pi)/(4))+i sin(-(3 pi)/(4)) the real and imaginary parts in the cartesian form respectively,are a).-1 and -1 b)-1 and 0 c).0 and -1 d)-1 and 1

write in the form A+iB[1+cos((pi)/(3))+i sin((pi)/(3))]^(6)

The continued product of the four values of (cos((pi)/(3))+i sin((pi)/(3)))^((3)/(4)) is