Evaluate `int sqrtt dt`

Evaluate indefinite integration. (i) x=intdt " " (ii) int t dt " " (iii) x=int (2t) dt" " (iv) x=int (t^(2)) dt " " (v) x=int (-(2)/(t^3))dt

Evaluate int^t _0 A sin omega dt where A and omega are constants.

Evaluate int(t^(2))/(sqrt(1-t^(2)))dt

Evaluate int_(0)^(oo)(dt)/(t)

int t/(t+b^2) dt

int tsint^(2)dt

For x in (0 , (5pi)/(2)) define f(x) = underset(0)overset(x)(int) sqrtt sin t dt Then has :

A=int_(1)^(sin theta)(t)/(1+t^(2))dt;B=int_(1)^(cos ec theta)(1)/(t(1+t^(2)))dt then find the value of the given determinant