For two positions of a lens, the images are obtained on a fixed screen. If the size of the object is 4.00cm and the size of the diminished image is 2.40cm ,the size of the other image in "cm is

If x_(1) is the size of the magnified image and x_(2) is the size of the diminished image in lens displacement method, then the size of the object is

If x_(1) is the size of the magnified image and x_(2) is the size of the diminsghed image in lens displacement method, then the size of the object is

A plane mirror is used to obtain an image of an object. Compare the size of the image formed in it to the size of the object.

The image formed by a concave mirror is twice the size of the object. The focal length of the mirror is 20 cm. The distance of the object from the mirror is//are

When the distance between the object and the screen is more than 4 f . We can obtain image of the object on the screen for the two positions of the lens. If is called displacement method. In one case, the image is magnified and in the other case, it is diminished. If I_(1) and I_(2) be the sized of the two images, then the size of the object is

(a) A screen is kept at a distance of 1m from the object. A converging lens between the object and the screen, when placed at any of the two positions which are 60cm apart, forms a sharp image of the object on the screen. Find the focal length of the lens. (b) In the two positions of the lens, lateral size of the image is 4cm and 9cm. Find the size of the object.

The magnifications for two positions of image of the same lens are 3 and 2, of a fix point object on a fix screen when the distance between the two positions of lens is 30 cm . The focal lengths of the lens is

The focal length of a concave mirror is 30 cm.Find the position of the object in front of the mirror,so that the image is three times the size of the objects.

When a lens is inserted between an object and a screen which are fixed distance apart the size of the image is either 6 cm or 2/3 cm. Find size of the object

An object is placed 12cm in front of a lens to form an image on a screen. The size of the image is twice that of the object. What is the distance between the object and the image?