20g of sample of `CaCO_(3)` gave 1.68L of `CO_(2)` at STP with excess HCl.Then the purity of `CaCO_(3)` sample is

10 g of CaCO_(3) contains

70 g of a sample of magnesite on treatment with excess of HCl gave 11.2 L of CO_(2) at STP. The percentage purify of the sample

10 g of CaCO_(3) contains :

62.5 gm of a mixture of CaCO_(3) and SiO_(2) are treated with excess of HCl and 1.1 gm of CO_(2) is produced. What is mass % CaCO_(3) in the mixture.

The volume of CO_(2) at STP obtained by heating 1 g of CaCO_(3) will be

18.4 gram mixture of MgCO_(3) and CaCO_(3) produce 4.48 litre of CO_(2) at STP. Then calculate the amount of MgCO_(3) and CaCO_(3) in mixture.

20 g mixture of Na_(2)CO_(3) and CaCO_(3) is gently heated. On heating this sample produces 2.24 litre of CO_(2) at STP. Calculate the % weight of Na_(2)CO_(3) in that sample.

500 g impure sample of CaCO_(3) on heating gives 70 g of CaO . Percentage impurities in sample is

10 g of a sample of a mixture of CaCl_(2) and NaCl is treated to precipitate all the calcium as CaCO_(3) . This CaCO_(3) is heated to convert all the Ca to CaO and the final mass of CaO is 1.62 g.The percent by mass of CaCl_(2) in the origial mixture is

What volume of CO_(2) at STP will evolve when 1 g of CaCO_(3) reacts with excess of dill . HCI ?