A new scale `N` of temperature is divided in such a way that the freezing point of water is `100^(@)N` and boiling point is `400^(0)N` .The Celsius and new temperature scale readings will be same at

In Kelvin scale what is the boiling point of water

The disjunction of the statement:"Freezing point of water is 0 ^o and Boiling point is 100 ^o ."

The freezing point on a thermometer is marked as -20^(@) and the boiling point as 130^(@) . A temperature of human body (34^(@)C) on this thermometer will be read as

On a new scale of temperature (which is linear) and called the W scale. The freezing and boiling points of water are 39^(@)W and 239^(@)W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39^(@)C on the Celsius scale?

On a new scale of temperature (which is linear) and called the W scale. The freezing and boiling points of water are 39^(@)W and 239^(@)W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39^(@)C on the Celsius scale?

In a termperature scale X ice point of water is assigned a value of 20^(@) X and the boiling point of water is assiggned a value of 220^(@) X . In another scale Y the ice poiny of water is assigned a value of -20^(@) Y and the boiling point is given a value of 380^(@)Y . Then temperature on both the scales will be same is

If the boiling point of water is 95^(@)F , what will be reduction at celsius scale?

What is the trend of boiling points of hydrides of N, O and F ?

Liquid oxygen freezes at - 218.4 ^(@)C and boils at - 183^(@)C . Express these temperatures in Fahrenheit scale.

The freezing point of water on a thermometer is marked as 20unit and the boiling point as 120 unit. Find the value of temperature 80^(@)C on this thermometer.