Three light waves combine at a certain point where thcir electric field components are` E 1 = E 0 sin ω t ,
E 2 = E 0 sin ( ω t + 60 ∘ )
, E 3 = E 0 sin ( ω t − 30 ∘ ) .` Find their resultant component

The dimensional formula of [E_0(dphi_E)/dt] is (where phi_E electric flux and e_0 is permittivity of air)

The dimensions of 1/2 in_(0) E^(2) ( in_(0) : permittivity of free space, E: electric field) is-

An electromagnetic wave is propagating in vacuum along z-axis, the electric field component is given by E_(x)=E_(0)sin (kz-omegat) . Then magnetic components is

The dimensions of 1/2 epsilon_(0)E^(2) (epsilon_(0)= permittivity of free space, E= electric field) is

Two coherent sources emit light waves which superimpose at a point where these can be expressed as E_(1) = E_(0) sin(omega t + pi//4) E_(2) = 2E_(0) sin(omega t - pi//4) Here, E_(1) and E_(2) are the electric field strenghts of the two waves at the given point. If I is the intensity of wave expressed by field strenght E_(1) , find the resultant intensity

Find dy/dx x=e^t (sin t + cos t ),y=e^t(sin t -cos t)

If lambda=int_0^1(e^t)/(1+t) , then int_0^1e^tlog_e(1+t)dt is equal to

The surface of a metal of work funcation phit is illumicated by light whose electric field component varies with time as E = E_(0) [1 + cos omegat] sinomega_(0)t . Find the maximum kinetic energy of photonelectrons emitted from the surface.

Find the area bounded by the curve y=sinxb e t w e e nx=0a n dx=2pidot

The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field