Home
Class 11
PHYSICS
One mole of an ideal monoatomic gas (deg...

One mole of an ideal monoatomic gas (degree of freedom =3),2 moles of an ideal diatomic gas (degree of freedom=5) and 3 moles of an ideal triatomic gas(degree of freedom=6) are mixed. `gamma_(eq)` for the mixture is `alpha/beta`. Here `alpha` and `beta` are integers. Find the minimum value of `(alpha-beta)/2`.

Promotional Banner

Similar Questions

Explore conceptually related problems

One mole of a monoatomic gas at 300K is mixed with two moles of diatomic gas (degree of freedom = 5) at 600K. The temperature of the mixture will be

One mole of an ideal monoatomic gas is mixed with 1 mole of an ideal diatomic gas The molar specific heat of the mixture at constant volume is .

One mole of an ideal monoatomic gas is mixed with one mole of an ideal diatomic gas. The molar specific heat of the mixture at constant volume is (in Calories )

Calculate the total number of degree of freedom for a mole of diatomic gas at STP.

2 moles of monoatomic gas are mixed with "1" mole of a diatomic gas.Then "y" for the mixture is:

10 moles of an ideal monoatomic gas at 10^(@)C are mixed with 20 moles of another monoatomic gas at 20^(@)C . Then the temp. of the mixture is

When 1 mole of a monatomic gas is mixed with 3 moles of a diatomic gas, the value of adiabatic exponent gamma for the mixture is