in the damped oscillator, the mass m of the block is 200 g, k = 90 N/m and the damping constant b is 40 g/s. Find the time taken for its mechanical energy to drop to half of its initial value

For a damped oscillator which follow the equation vecF=-kvecx-bvecV the mass of the block is 100 gm K=100N/M and the damping constant is 20 gm/sec. thhen find the time taken for its mechanical energy to drop to one-fourth of its initial value.

For the damped oscillator shown in Fig, the mass of the block is 200 g, k = 80 N m^(-1) and the damping constant b is 40 gs^(-1) Calculate The period of oscillation

For the damped oscillator shown in Figure, the mass m of the block is 400 g, k=45 Nm^(-1) and the damping constant b is 80 g s^(-1) . Calculate . (a) The period of osciallation , (b) Time taken for its amplitude of vibrations to drop to half of its initial value and (c ) The time taken for its mechanical energy to drop to half its initial value.

For the small damping oscillator, the mass of the block is 500 g and value of spring constant is k = 50 N/m and damping constant is 10 gs^(-1) The time period of oscillation is (approx.)

A block of mass 200 g executing SHM under the influence of a spring of spring constant k=90Nm^(-1) and a damping constant b=40gs^(-1) . The time elapsed for its amplitude to drop to half of its initial value is (Given, ln (1//2)=-0.693 )

Find the total energy of oscillations if mass of the body is 100g A=1m , omega = 2

How many time constants will elapse before the current in a charging R-C circuit drops to half of its initial value?

The half life of a radioactive substance is 20s, the time taken for the sample to decay by 7//8^(th) of its initial value is

The displacement of a damped harmonic oscillator is given by x(t)-e^(-0.1t) cos(10pit+varphi) .Here t is in seconds. The time taken for its amplitude of vibration to drop to half of its initial value is close to :