A body is projected at an angle of `30^(@)` with the horizontal with momentum p. At its highest point the magnitude of the momentum is

If a body is projected with an angle theta to the horizontal, then

A body is projected at an angle of 30^@ with the horizontal and with a speed of 30 ms^-1 . What is the angle with the horizontal after 1.5 s ? (g = 10 ms^-2) .

A body is projected with a speed u at an angle of 30^(@) with the horizontal at t=0 . The angular momentum of the body about the point of projection is (xsqrt(3)mu^(3))/(64g) at t=(3u)/(4g) . Find the value of x ?

A body of mass 1kg is projected with velocity 50 ms^(-1) at an angle of 30^(@) with the horizontal. At the highest point of its path a force 10 N starts acting on body for 5s vertically upward besids gravitational force, what is horizontal range of the body (Take, g = 10 ms^(-2))

A body of mass 0.5 kg is projected under the gravity with a speed of 98 m//s at an angle of 30^(@) with the horizontal. The change in momentum (in magnitude) of the body when it strikes the ground is

A projectile is fired at an angle of 45^(@) with the horizontal. Elevation angle of the projection at its highest point as seen from the point of projection is

A particle of mass 1 kg is projected at an angle of 30^(@) with horizontal with velocity v = 40 m/s . The change in linear momentum of the particle after time t = 1 s will be (g = 10 m// s^(2) )

A body is projected at angle 30° to the horizontal with a velocity 50 ms^(-1) maximum height of projectile is

A ball whose kinetic energy is E , is projected at an angle of 45(@) to the horizontal . The kinetic energy of the ball at the highest point of its flight will be

When a body is projected at an angle with the horizontal in the uniform gravitational field of the earth, the angular momentum of the body about the point of projection, as it proceeds along its path