Ratio of maximum to minimum intensities in YDSE is `25:9`. Calculate ratio of widths of slits:
`(1) 18:3`
`(2) 4:1`
`(3) 8:1`
`(4) 16:1`

Assertion: Ratio of maximum intensity and minimum intensity in interference is 25:1 . The amplitudes ratio of two waves should be 3:2 . Reason: I_(max)/I_(min) = ((A_1+A_2)/(A_1-A_2))^2 .

In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is 9:1 the ratio of amplitudes of coherent sources is

The ratio of the intensities two waves is 1 : 9 The ratio of their amplitudes is

A transparent glass plate of thickness 0.5 mm and refractive index 1.5 is placed infront of one of the slits in a double slit experiment. If the wavelength of light used is 6000 A^(@) , the ratio of maximum to minimum intensity in the interference pattern is 25/4. Then the ratio of light intensity transmitted to incident on thin transparent glass plate is

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1 . The amplitudes of the coherent sources are in the ratio

In the case of interference, the maximum and minimum intensities are in the ratio 16 : 9. Then

If the heights of two cones are in the ratio of 1:4 and the radii of their bases are in the ratio 4:1, then the ratio of their volumes is (a) 1:2 (b) 2:3 (c) 3:4 (d) 4:1

The circumferences of two circles are in the ratio 3: 4. The ratio of their areas is (a) 3:4 (b) 4:3 (c)9:16 (d) 16 :9

The ratio of maximum to minimum intensity due to superposition of two waves is 49/9 . Then, the ratio of the intensity of component waves is.

An interference pattern has maximum and minimum intensities in the ratio of 36:1, what is the ratio of theire amplitudes?