A bullet of mass 10 g moving with a speed of 30 m/s hits an ice block (0 degrees) of 990g kept at rest on a frictionless floor and gets embedded in it. If ice takes 50% of K.E, the amount of ice melted(in grams) approximately is (1 J=4.2/ cal) (Latent heat of Ice= 80cal/g)

A bullet of mass 10 g moving with a speed of 20 m//s hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if 50% of the lost kinetic energy goes to ice? (Temperature of ice block = 0^@C .)

A bullet of mass 10 g moving with a speed of 20 m//s hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if 50% of the lost kinetic energy goes to ice? (Temperature of ice block = 0^@C .)

If a ball of 80 kg mass hits an ice cube and temperature of ball is 100 .^(@)C , then how much ice converted into water ? (Specific heat of ball is 0.2 cal g^(-1) , Latent heat of ice = 80 cal g^(-1) )

A coil of water of resistance 50 Omega is embedded in a block of ice and a potential difference of 210 V is applied across it. The amount of ice which melts in 1 second is [ latent heat of fusion of ice = 80 cal g^(-1) ]

Rays from the sun ar focuseed by a lens of diameter 5 cm on to a block of ice and 10 g of ice is melted in 20 min. Therefore the heat from the sun reaching the earth per min per square centrimetre is (Latent heat of ice L = 80 cal g^(-1) )

A bullet weighing 10 g and moving with a velocity 300 m/s strikes a 5 kg block of ice and drop dead. The ice block is kept on smooth surface. The speed of the block after the the collision is

When 1 kg of ice at 0^(@)C melts to water at 0^(@)C , the resulting change in its entropy, taking latent heat of ice to be 80 cal//g is

A refrigerator converts 100 g of water at 25^(@)C into ice at -10^(@)C in one hour and 50 minutes. The quantity of heat removed per minute is (specific heat of ice = 0.5 "cal"//g^(@)C , latent heat of fusion = 80 "cal"//g )

One end of a brass rod of length 2.0 m and cross section 1cm^2 is kept in steam at 100^@C and the other end in ice at 0^@C . The lateral surface of the rod is covered by heat insulator. Determine the amount of ice melting per minute. Thermal conductivity of brass is 110 W//m-K and specific latent heat of fusion of ice is 80 cal//g .

An iron ball of mass 0.2 kg is heated to 10^(@)C and put into a block of ice at 0^(@)C . 25 g of ice melts. If the latent heat of fusion of ice is 80 cal g^(-1) , then the specific heat of iron in cal g^(-1^(@))C is