The formula of a gaseous hydrocarbon which requires 6 times of its own volume of `O_(2)` for complete oxidation and produces 4 times its own volume of `CO_(2)` is `C_(x)H_(y)` .The value of y is

The vapour of an organic compound requires three times its own volume of oxygen for complete combustion and produces twice its own volume of carbon dioxide . Which of the following compounds would give these results ?

8c.c. of gaseous hydrocarbon requires 40c.c. of O_(2) for complete combustion. Identify hydrocarbon.

A gaseous paraffin requires five times its volume of oxygen for complete combustion. How many carbon atoms are present in a molecule of that paraffin?

At STP , for complete combustion of 3 g C_(2)H_(6) the required volume of O_(2) will be -

The volume of O_(2) at STP required for the complete combustion of 4 g CH_(4) is

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

A gaseous hydrocarbon consumed 5 times its volume of oxygen as for combustion. The volume of CO_(2) produced in the reaction is thrice the volume of hydrocarbon under the same conditions What is the ratio of molecular weight to emperical formula weight of the hydrocarbon?

At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O_(2) for complete combustion, and 40 mL of CO_(2) is formed. The formula of the hydrocarbon is:

At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O_(2) for complete combustion, and 40 mL of CO_(2) is formed. The formula of the hydrocarbon is:

A gaseous hydrocarbon consumed 5 times its volume of oxygen as for combustion. The volume of CO_(2) produced in the reaction is thrice the volume of hydrocarbon under the same conditions How many grams of water is produced by combustion of 0.1 mol of the givenn hydrocarbon?