i^2 + i^4 + i^6 + ...... (2n + 1) पदों ...

`i^2 + i^4 + i^6 + ...... (2n + 1) ` पदों तक = ? (a) -1 (b) 1 (c) - i (d) i

i^2 + i^4 + i^6 + ...... (2n + 1) पदों तक = ? (a) -1 (b) 1 (c) - i (d...
Text Solution
|
The value of (i^5+i^6+i^7+i^8+i^9)/(1+i) is (a) 1/2(1+i) (b) 1/2(1-...
Text Solution
|
The value of i^(2n)+i^(2n+1)+i^(2n+2)+i^(2n+3), where i=sqrt(-1), is
Text Solution
|
Simplifiy i^(2)+i^(4)+i^(6)+.....+(2n+1) terms
Text Solution
|
Find the value of 1+i^(2)+i^(4)+i^(6)+...+i^(2n), wherei=sqrt-1 and...
Text Solution
|
1+i^2+i^4+i^6+.........+i^(2n)=
Text Solution
|
I : i^2+i^4+i^6+......(2n+1) terms = - 1 II : 1+i^2+i^4+i^6+.........
Text Solution
|
1+i^(2)+i^(4)+i^(6)+....+i^(2n) है
Text Solution
|
i^(2)+i^(4)+i^(6)+…(2n+1) पदों का मान होगा
Text Solution
|