What is the shortest wavelength line in the Paschen series of `Li^(+2)` ion ?

A `R/9`
B` 9/R`
C `1/R`
D `(9R)/4`

What is the shortest wavelength present in the Paschen series of spectral lines?

What is the shortest wavelength present in the Paschen series of spectral lines?

What is the shortest wavelength present in the Paschen series of spectral lines?

The shortest wavelength in the balmer series is (R=1.097xx10^7m^-1)

The shortest wavelength of transition in Paschen series of He^(+) ion in nanometer (nm) is (1/(R_(H))=91.12nm) .

The shortest wavelength of He^(+) in Balmer series is x . Then longest wavelength in the Paschene series of Li^(+2) is :-

Calculate the shortest wavelength of light emitted in the Paschen series of hydrogen spectrum. Which part of the electromagnetic spectrum, does it belong ? ( Given : Rydberg constant , R = 1.1 xx 10^(7)m^(-1)

The largest wavelength in Paschen series of Li^(+2) is (16x)/(9) .The largest wavelength of Balmer series in He^(+) is : (A) x, (B) 1.2x, (C) 1.4x, (D) (5x)/(9)

The difference between the wave number of 1st line of Balmer series and last line of Paschen series for Li^(2+) ion is :

If the sum to the infinity of the series 3+5r+7r^2+.... is 44/9 then find the value of r