The ionization potential of an element is 5.23eV .This can also be expressed as .......K.cals/mole

The first ionization potential (eV) of N and P respectively are

The ionization potential of sodium is 5.48 eV the I.P of potassium is likely to be

can molecular mass be expressed as grams per mole?

If f(x)=sqrt(x^(2)) , then f(x) can also be expressed as

The second ionization potential of elements is invariable higher than first ionization potential because:

Mass of an atom of an element X is 2.66xx10^(-23) g. How can this mass be expressed in terms of amu ?

The ionisation potential of hydrogen is 13.60 eV . Calculate the energy required to produce one mole of H^(o+) ion (1 eV = 96.3 kJ mol^(-1)) .

The first, second, third and fourth, ionization potential values of an element are 8.4, 25.15, 37.92 and 256.3eV respectively. The element is

The ionisation potential and electron affinity of an element "X" are 275 and 86 kcal/mole. Then the electronegativity of "X" according to Mulliken scale is

The ionisation potentials of Li and K are 5.4 and 4.3 eV respectively. The ionization potential of Na will be: