Drops of liquid of density "d" are floating half immersed in a liquid of density ρ If surface tension of the liquid is "T," the radius of the drop is:

A drop of liquid of density rho is floating half-immersed in a liquid of density d . If sigma is the surface tension the diameter of the drop of the liquid is

A sphere of density rho is half submerged in a liquid of density sigma and surface tension T. The sphere remains in equilibrium. Find radius of the sphere (assume the force due to surface tension acts tangentially to surface of sphere)

A solid of density D is floating in a liquid of density d. If upsilon is the volume of solid submerged in the liquid and V is the total volume of the solid, then upsilon//V equal to

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V . If T is the surface tension of the liquid, then

A block of density rho floats in a liquid with its one third volume immersed. The density of the liquid is

A liquid is coming out from a vertical tube. The relation between the weight of the drop W , surface tension of the liquid T and radius of the tube r is given by, if the angle of contact is zero

A liquid of diameter D breaks up into 64 tiny drops. If the surface tension of the liquid is sigma what is the change in energy?

A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72 . If relative density of silver is 10 , then tension in the string will be

A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72 . If relative density of silver is 10 , then tension in the string will be

A body of density rho is immersed in a liquid of density rho_(L) .State condition when the body will (i) float (ii) sink in liquid.