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Moment of Inertia | IIT JEE | NEET | CBSE

For a uniform sphere a small cavity is formed as shown STATEMENT-1 : Moment of inertia of the sphere about AA is greater than moment of inertia about BB' . and STATEMENT-2 : Mass removed was more closer to the axis AA.

A bar magnet of moment of inertia I is vibrated in a magnetic field of inducton is 0.4xx10^(-4)T . The time period period of vibration is 12 sec. The magnetic moment of the magnet is 120Am^(2) . The moment of inertia of the magnet is ("in"kgm^(2)) approximately

The moment of inertia of a uniform rod about a perpendicular axis passing through one end is I_(1) . The same rod is bent into a ring and its moment of inertia about a diameter is I_(2) . Then I_(1)//I_(2) is

Assertion:The moment of inertia of rigid body depends only on the mass of the body, its shape and size. Reason: Moment of inertia I = MR^2 where M is the mass of the body and R is the radius vector.

Figure shows a body of arbitrary shape 'O is the centre of mass of the body and mass of the body is M. If moment of inertia about axis CC is Icc'. then moment of inertia about axis AA' (I AA')will be equal to

A disc has mass 9 m. A hole of radius R/3 is cut from it as shown in the figure. The moment of inertia of remaining part about an axis passing through the centre 'O' of the disc and perpendicular to the plane of the disc is :

The moment of inertia of a ring of mass M and radius R about PQ axis will be

Moment of inertia of a disc about an axis parallel to diameter and at a distance x from the centre of the disc is same as the moment of inertia of the disc about its centre axis. The radius of disc is R . The value of x is

Moment of inertia of a rod of mass m and length l about its one end is I . If one-fourth of its length is cut away, then moment of inertia of the remaining rod about its one end will be