In third orbit of hydrogen atom wavelength of revolving `e^(-)` is `lambda` .Calculate its circumference

The circumference of second orbit of hydrogen atom, if the wavelength of electron is 5 xx 10^(-9)m will be

An electron is moving in Bohr's fourth orbit. Its de Broglie wavelength is lambda . What is the circumference of the fourth orbit?

The circumference of the 4^(th) bohr orbit of hydrogen is 5.32 nm .The wavelenght of electron revolving in the first bohr orbit will be

Find the de Broglie wavelength of revolving electron for the Bohr's first orbit of circumference 2pir .

If the wavelength of photon emitted due to transition of electron from third orbit to first orbit in a hydrogen atom is lambda then the wavelength of photon emitted due to transition of electron from fourth orbit to second orbit will be

The wavelength of radiation emitted is lambda_(0) when an electron jumps from the third to the second orbit of hydrogen atom. For the electron jump from the fourth to the second orbit of hydrogen atom, the wavelength of radiation emitted will be

the wavelength of radiation emitted is lambda_0 when an electron jumps. From the third to second orbit of hydrogen atom. For the electron jumping from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be

When the electron in hydrogen atom jumps from the second orbit to the first orbit, the wavelength of the radiation emitted is lambda . When the electron jumps from the third to the first orbit . The wavelenth of the radiation emitted is

The circumference of the second Bohr orbit of electron in hydrogen atom is 600nm . The potential difference that must be applied between the plates so that the electron have the de Broglie wavelength corresponding in this circumference is

For an electron in the third orbit Bohr hydrogen atom, the moment of linear momentum is