Conversion of ethyl bromide to ethylene is an example of:

Options

A. Hydrohalogenation
B. Intramolecular dehydrohalogenation
C. Dehydration
D. Hydration

Answer

To convert ethyl bromide (C2H5Br) to ethylene (C2H4), we can follow these steps:

### Step 1: Identify the Reactants and Products
- **Reactant**: Ethyl bromide (C2H5Br)
- **Product**: Ethylene (C2H4)

### Step 2: Understand the Reaction Type
The conversion of ethyl bromide to ethylene involves the elimination of hydrogen bromide (HBr). This type of reaction is known as an elimination reaction.

### Step 3: Write the Reaction
The elimination of HBr from ethyl bromide can be represented as:
\[ \text{C}_2\text{H}_5\text{Br} \rightarrow \text{C}_2\text{H}_4 + \text{HBr} \]

### Step 4: Identify the Reagent
To facilitate this reaction, we can use alcoholic potassium hydroxide (KOH). Alcoholic KOH acts as a strong base that promotes the elimination of HBr.

### Step 5: Mechanism of the Reaction
1. The alcoholic KOH will abstract a proton (H⁺) from the ethyl bromide.
2. The bromine atom (Br) will leave, resulting in the formation of a double bond between the two carbon atoms, leading to the formation of ethylene.

### Step 6: Final Reaction
The complete reaction can be summarized as:
\[ \text{C}_2\text{H}_5\text{Br} + \text{KOH (alc)} \rightarrow \text{C}_2\text{H}_4 + \text{HBr} + \text{KBr} \]

### Conclusion
Thus, the conversion of ethyl bromide to ethylene is an example of an **elimination reaction**.

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