When chloroform is heated with aqueous NaOH, it gives:

Options

A. Formic acid
B. Sodium formate
C. Acetic acid
D. Sodium acetate

Answer

To determine the product of the reaction between chloroform (CHCl3) and aqueous sodium hydroxide (NaOH), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chloroform (CHCl3) and aqueous sodium hydroxide (NaOH).

### Step 2: Understand the Reaction Conditions
When chloroform is heated with aqueous NaOH, it undergoes a hydrolysis reaction. The presence of NaOH indicates that it is a basic medium, which will facilitate the reaction.

### Step 3: Reaction Mechanism
In the reaction, chloroform (CHCl3) reacts with NaOH to form a trihydroxy compound (CHOH)3. This compound is unstable due to the presence of multiple hydroxyl (OH) groups on a single carbon atom.

### Step 4: Elimination of Water
Due to the instability of the trihydroxy compound, it will lose a water molecule (H2O) to form a carbonyl compound. The resulting compound will be a carbonyl compound (C=O), which is an acid.

### Step 5: Formation of Sodium Formate
Since NaOH is present in the solution, it will react with the formed acid (which is formic acid, HCOOH) to produce sodium formate (HCOONa). Thus, the final products of the reaction are sodium formate and water.

### Final Answer
When chloroform is heated with aqueous NaOH, it gives sodium formate (HCOONa) and water.

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