What will be sulphide ion concentration of a dilute solution that has been saturated with 0.1M `H_2S` if the pH of the solution is 3? `K_``a_1` = `1 times 10^(-7)` ; `K_``a_2` = `1.3 times 10^(-13)`

Find the concentration of H^(o+), HCO_(3)^(Θ) , and CO_(3)^(-2) in a 0.01M solution of carbonic acid if the pH of solution is 4.18 . K_(1) = 4.45 xx 10^(-7),K_(2) = 4.69 xx 10^(-11)

Find the concentration of H^(o+), HCO_(3)^(Θ) , and CO_(3)^(-2) in a 0.01M solution of carbonic acid if the pH of solution is 4.18 . K_(1) = 4.45 xx 10^(-7),K_(2) = 4.69 xx 10^(-11)

What is the hydronium ion concentration of a 0.25 M HA solution? (K_(a)=4xx10^(-8))

A solution contains 0.10 M H_2S and 0.3 HCl Calculate the concentration of S^(2-) and HS^(-) ions in the solution . For H_2S , K_(a_1) = 1 xx 10^(-7) and K_(a_2) = 1.3 xx 10^(-13)

The concentration of hydronium ions in a cup of black coffee is 1.3 xx 10^(-5) M. What will be the pH of the coffee?

What is the minimum pH required to prevent the precipitation of Zn^(+2) in a solution that is 0.05 M ZnCl_(2) and saturated with 0.2M H_(2)S (Given : K_(sp) ( ZnS) = 10^(-20) and Ka_(1) xx Ka_(2) of H_(2)S = 10^(-20) )

Calculate the concentration of all species of significant concentrations presents in 0.1 M H_(3)PO_(4) solution. lf K_(1) = 7.5 xx 10^(-3), K_(2) = 6.2 xx 10^(-8), K_(3) = 3.6 xx 10^(-13)

What is the minimum pH required to prevent the precipitation of ZnS in a solution that is 0.01 M ZnCl_(2) and saturated with 0.10 M H_(2)S ? ["Given" :K_(sp)=10^(-21),K_(a_1)xxK_(a_2)=10^(-20)]

The pH of a solution of NH_4Cl is 4.86 .Calculate the molar concentration fo the solution if K_b= 1.0 xx 10^(-5) and K_w = 1.0 xx 10 ^(-14)

A solution containing both Zn^(2+) and Mn^(2+) ions at a concentration of 0.01M is saturated with H_(2)S . What is pH at which MnS will form a ppt ? Under these conditions what will be the concentration of Zn^(2+) ions remaining in the solution ? Given K_(sp) of ZnS is 10^(-22) and K_(sp) of MnS is 5.6 xx 10^(-16), K_(1) xx K_(2) of H_(2)S = 1.10 xx 10^(-21) .