If intermolecular forces vanish among water molecules, then volume occupied by 1.8g `H_2O` (l) at STP is: (A) 2.24 litre (B) 22.4 litre (C) 1.8 mL (D) 2.24mL

Calculate the volume occupied by 2.4 g of a gas at STP when its vapour density is 11.2

The density of water is 1g/mL. Water is the volume occupied by 1 molecule of water ?

The density of water is 1g/mL. What is the volume occupied by 1 molecule of water ?

Vapour density of a gas is 11.2. Volume occupied by 2.4 g of this at STP will be

How many molecules are there in 22.4 L of H_(2) at STP?

Number of electron in 1.8mL of H_(2)O(l)

The volume of 10 volume of H_2O_2 required to liberate 500mL of O_2 at STP is

4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be :

On carrying out the electrolysis of acidified water, the volume of hydrogen liberated at STP condition is 22.4L . The volume of oxygen liberated is a.22.4 L b.44.8 L c.11.2 L d.2.24 L

What volume would a gas occupy at 2 atm. and 227^(@)C if its volume at S.T.P. is 2-5 litres.