If `|[x,6,2],[1,7,3],[x,1,1]|=0`, then `x=?`.

|[3+x,5,2] , [1,7+x,6], [2,5,3+x]|=0

Solve for x: /_\=|[2x,3,1],[4,6,x],[3x,1,1]| = 0

If f(x)= |[2cos x,1,0],[1,2cos x,1],[0,1,2cos x]| then f'((pi)/(6))= A.-5, B.-7, C. -sqrt(3) , D.4

Find the value of x, if |[(3+x), 5, 2],[1, (7+x), 6], [2, 5, (3+x)]| = 0

If x+y=[[1,4,3] , [-2,5,6] , [7,0,2]] and x-y=[[3,2,5] , [4,1,2] , [1,0,4]] then find x and y

If 2[[3,4],[5,x]]+[[1,y],[0,1]]=[[7,0],[10,6]] then find (x-y)

If A=[{:(1,1,1),(1,0,2),(3,1,1):}] , find A^(-1) . Hence, solve the system of equations : x+y+z=6 , x+2z=7 , 3x+y+z=12

If x={0,1,2,3,4,5,6,7,8,9,10} and Y={ 1,3,5,7,9} then X-Y=___.

If (3(x^2 +1)-7x)/3x =6, x ≠ 0 , then the value of sqrtx + 1/(sqrtx) is: यदि (3(x^2 +1)-7x)/3x =6, x ≠ 0 , है, तो sqrtx + 1/(sqrtx) का मान क्या होगा?