If `0ltxltpi/2` and `|[cosx,-2],[-1/4,tanx]|=0`, then `x=?`.

If 0 lt x lt pi and cosx+sinx = (1)/(2) , then tanx is :

If 0ltxltpi/4andcosx+sinx=5/4 , then the value of 16(cosx-sinx)^2 is ___________ .

0

if f(x)=|[2cosx,1,0],[x-pi/2,2cosx,1],[0,1,2cosx]| then (df)/(dx) at x=pi/2 is

Let f(x) be defined as follows: f(x)=[((cosx-sinx)^(cose cx),-pi/2ltxlt0),(a,x=0),(((e^(1/x)+e^(2/x)+e^(3/x))/(ae^(2x)+be^(3x)),0ltxltpi/2)] if f(x) is continuous x=0 , then (a)a=1/e(b)a=e(c) b=1/e (d)b=e

Solve the equation (cosx-sinx)(2tanx+2)=0

If (2cosx-1)(3+2cosx)=0, 0lexle2pi, then x=

2tanx-cotx+1=0

If -pi//2ltxltpi//2 , and the sum to infinite terms of the series cosx+(2)/(3)cosxsin^(2)x+(4)/(9)cosxsin^(4)x+ . . . if finite then