Two large parallel metal plates (`3.00mm` apart ) are charged to a potential difference of `12V` .They are now disconnected from the battery and pulled apart to `5.00mm` .What is the new potential difference between plates?

A parallel plate capacitor is charged to a potential difference of 10 volts. After disconnecting the battery, distance between the plates of capacitor is decreased by using nonconducting handles. The potential difference between the plates will

A pararllel plate capacitor has plates of area A and separation d and is charged to potential diference V . The charging battery is then disconnected and the plates are pulle apart until their separation is 2d . What is the work required to separate the plates?

A parallel plate capacitor charged to potential difference V_0 . The variation of potential V from x= 0 to x= d is best described by

A parallel-plate capacitor has plates of area A and separation d and is charged to a potential difference V . The charging battery is then disconnected, and the plates are pulled apart until their separation is 2d . Derive expression in terms of A, d and V for (a) the new potential difference (b) the initial and final stored energies, U_i and U_f and (c) the work required to increase the separation of plates from d to 2d .

A capacitor of capacitance C is charged to a potential difference V from a cell and then disconncted from it. A charge +Q is now given to its positive plate. The potential difference across the capacitor is now

A capacitor of capacitance C is charged to a potential difference V from a cell and then disconncted from it. A charge +Q is now given to its positive plate. The potential difference across the capacitor is now

A capacitor of capacitnace C is charged to a potential difference V and then disconnected from the battery. Now it is connected to an inductor of inductance L at t=0. Then

The plates of a parallel plate capacitor are charged to a potential difference of 117 V and then connected across a resistor. The potential difference across the capacitor decreases exponentially with to time.After 1s the potential difference between the plates is 39 V, then after 2s from the start, the potential difference (in V) between the plates is

Two capacitors of capacitances 3 muF and 6 muF are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

Ten capacitors are joined in parallel and charged with a battery up to a potential V . They are then disconnected from the battery and joined in series. Then potential of the combination will be .