2 moles of `H_2O_2` is treated with equivalent amount of `KMnO_4` in the presence of `H_2SO_4` then moles of `O_2` gas liberated is______

If one mole of H_(2)SO_(4) reacts with one mole of NaOH, equivalent weight of H_(2)SO_(4) will be :

0.2 g of a sample of H_(2)O_(2) required 10 mL of 1 N KMnO_(4) in a titration in the presence of H_(2)SO_(4) Purity of H_(2)O_(2) is :

In a titration certain amount of H_(2)O_(2) is treated with y mole of KMnO_(4) in acidic medium. The left out KMnO_(4) when treated with X^(+) in basic medium oxidizes X^(+1) " to " X^(+6) and 0.2 M, x L of X^(+) was consumed. The mole of given H_(2)O_(2) solution is :

A bottle of H_2O_2 is labelled as 10 vol H_2O_2. 112mL of this solution of H_2O_2 is titrated against 0.04M acidified solution of KMnO_4 . Calculate the volume of KMnO_4 in terms of litre.

How many moles of FeC_2O_4 are required to reduce 2 " mol of " KMnO_4 in acidic medium?

A: When 4 moles of H_(2) reacts with 2 moles of O_(2) , then 4. moles of water is formed. R: O_(2) will act as limiting reagent.

For decolourisation of 1 "mol of" KMnO_(4) , the moles of H_(2)O_(2) required is

When 1 mole of KMnO_(4) is reacted with FeC_(2)O_(4) in acidic medium, then the reacted amount of FeC_(2)O_(4) is

When propyne is treated with aqueous (underset(2)(H)Sunderset(4)(O)) in presence of (HgS(4)(O)) , the major product is

A : H_2O liberate O_2 an reaction with KMnO_4 in acidic medium. R : KMnO_4 oxidises H_2O_2" to " O_2 .