A body released from a great height and falls freely towards the earth. Another body is released from the same height exactly one second later. Then the separation between the two bodies, two seconds after the release of the second body is

A body is released from a great height and falls freely towards the earth. Exactly one sec later another body is released. What is the distance between the two bodies 2 sec after the release of the second body ?

Two bodies begin a free fall from the same height at a time interval of Ns. If vertical separation between the two bodies is Lm after n seconds from the start of the first body, then n is equal to

A body falls from a certain bhight. Two seconds later another body falls from the same height. How long after the beginning of motion of the first body is the distance between the bodies twice the distance at the moment the second body starts to fall ?

A body released from the top of a tower of height h takes T seconds to reach the ground. The position of the body at T/4 seconds is

A body is released from the top of a tower of height h and takes 'T' sec to reach the ground. The position of the body at T/2 sec is

A body falls freely from a height 'h' after two seconds if accelaration due to gravity is reversed the body

A body is dropped from a height H. The time taken to cover second half of the journey is

A body is released form the top of a tower of height h meters. It takes t seconds to reach the ground. Where is the ball at the time t/2 sec ?

A ball is released from some height & rebounds with same speed after hitting the ground.If it travels 20m in first 8 seconds find the no of collision made.

A ball is released from some height & rebounds with same speed after hitting the ground.If it travels 20m in first 8 seconds find the no of collision made.