`I= int sin x/(1+cos^2 x)dx`

int(sin x)/(1-cos x)dx

(i) int (sin x)/(1+ cos x) dx. (ii) int (sin x)/(1+ cos x)^2 dx.

(1) I=int(1-sin x)/(cos x)dx

I=int(sin x)/(cos x)dx

int 1/(sin x cos x) dx

Evaluate (i) int_0^pi (x sin x)/(1+cos^2 x) dx Evaluate (ii) int_0^pi (4x sin x)/(1+ cos^2 x) dx

Find the following integrals: ( i ) int(sin x+cos x)dx( ii) int cos ecx(cos ecx+cos x)dx( iii) int(1-sin x)/(cos^(2)x)dx

int sin^(-1)(cos2x)*dx

int(1-sin x)/(cos+x)dx

(i) int sin^2x cos^3x dx (ii) int sin^3 x cos^2 x dx (iii) int sin^3 x cos^3 x dx