A ball is thrown from a field with a speed of 12.0 m/s at an angle of `45^0` with the horizontal. At what distance will it hit the field again ? Take `g=10.0 m/s^2`

A ball is thrown at a speed of 40 m/s at an angle of 60^0 with the horizontal. Find a. the maximum height reached and b. the range of te ball. Take g=10 m/s^2 .

A ball is thrown at a speed of 20 m/s at an angle of 30 ^@ with the horizontal . The maximum height reached by the ball is (Use g=10 m//s^2 )

A ball is projected from a point on the floor wilth a speed of 15 m/s at an angle of 60^0 with the horizontal. Will ilt hit a vertical wall 5 m away from the point of projection and perpendiculaer to the plane of projection without and perpendicular to the plane of projection without hitting the floor? will the answer differ if the wall is 22 m away?

The coach throws a baseball to a player with an initial speed of 20 m//s at an angle of 45^@ with the horizontal. At the moment the ball is thrown, the player is 50 m from the coach. At what speed and in what direction must the player run to catch the ball at the same height at which it was released? (g = 10 m//s^2) .

A football ils kicked with a velocity of 20 m/s at an angle of 45^0 wilth the horizontal. A. Find the time taken by the ball to strike the ground. b.Find the maximum height it reaches. C. How far away from the kick dows it hit the ground? Take g=10 m/s^2 .

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle 30 ^@ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? (g = 10 m//s ^ 2 )

A ball is thrown from the top of a tower with an initial velocity of 10 m//s at an angle of 30^(@) above the horizontal. It hits the ground at a distance of 17.3 m from the base of the tower. The height of the tower (g=10m//s^(2)) will be

A ball is projected form ground with a speed of 20 ms^(-1) at an angle of 45∘ with horizontal.There is a wall of 25m height at a distance of 10m from the projection point. The ball will hit the wall at a height.

An electric field is acting vertically upwards . A particle of mass 1 mg and charge -1 mu C is projected with a velocity 20m//s at an angle 45^(@) with the horizontal . Its horizontal range is 10 m, then the intensity of electric field is (g= 10 m//s^(2))

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)