`cos^(2)2x-cos^(2)6x=sin4x sin8x`

Prove that: cos^2 2x-cos^2 6x=sin4xsin8x

The number of distinct solutions of the equation 5/4cos^(2)2x + cos^4 x + sin^4 x+cos^6x+sin^6 x =2 in the interval [0,2pi] is

The number of distinct solutions of the equation 5/4cos^(2)2x + cos^4 x + sin^4 x+cos^6x+sin^6 x =2 in the interval [0,2pi] is

The values of x in (0, pi) satisfying the equation. |{:(1+"sin"^(2)x, "sin"^(2)x, "sin"^(2)x), ("cos"^(2)x, 1+"cos"^(2)x, "cos"^(2)x), (4"sin" 2x, 4"sin"2x, 1+4"sin" 2x):}| = 0 , are

If y=(sin^(4)x-cos^(4)x+sin^(2) x cos^(2)x)/(sin^(4) x+ cos^(4)x + sin^(2) x cos^(2)x), x in (0, pi/2) , then

Solve (sin^(2) 2x+4 sin^(4) x-4 sin^(2) x cos^(2) x)/(4-sin^(2) 2x-4 sin^(2) x)=1/9 .

If the maximum and minimum values of the determinant |(1 + sin^(2)x,cos^(2) x,sin 2x),(sin^(2) x,1 + cos^(2) x,sin 2x),(sin^(2) x,cos^(2) x,1 + sin 2x)| are alpha and beta , then

The solution of the equation "cos"^(2) x-2 "cos" x = 4 "sin" x - "sin" 2x (0 le x le pi) , is

Prove that : (cos x - cos y)^(2) + (sin x - sin y)^(2) = 4 sin^(2) ((x - y)/(2))

The function f(x) given by f(x)=(sin 8x cos x-sin6x cos 3x)/(cos x cos2x-sin3x sin 4x) , is