When a body accelerates by `beta t` ,what is the velocity after time t ,when its starts from rest.

If acceleration of a particle at any time is given by a = 2t + 5 Calculate the velocity after 5 s, if it starts from rest

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

A car starts from rest and moves with uniform acceleration 'a', At the same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet ? What is the velocity of car with respect to the bike at the time of meeting?

At t=0 , a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x=-(2//3)t^2+16t+2 . Find the initial velocity of the body and also find how long does the body take to come to rest? What is the acceleration of the body when it comes to rest?

The acceleration of a particle is increasing linearly with time t as bt. The particle starts from the origin with an initial velocity v_0 . The distance travelled by the particle in time t will be

Starting from rest, the acceleration of a particle is a=2(t-1). The velocity of the particle at t=5s is :-

A boat starting from rest aims perpendicular to the river with an acceleration of a=6t (where t= time) the boat starts from (2,0) of the coordinate system. Find equation of trajectory. Given velocity of river =u .

Starting from rest a body moves with uniform acceleration and acquires a velocity v after n seconds. Then its displacement in the last two seconds is

A body moves from rest with a uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 s after the start.