A and B being the fixed points (a, 0) and `(- a, 0)` respectively, obtain the equations giving the locus of P, when
`PA + PB= c`, a constant quantity.

If A and B be the points (3,4,5) and (-1,3,-7) respectively find the equation of set of ponts P such that PA^2+PB^2=k^2, where k is a constant.

If A(1,3) and B(2,1) are points,find the equation of the locus of point P such that PA=PB

Given two fixed points A and B and AB=6 .Then simplest form of the equation to thelocus of such that PA+PB=8 is

A(2,3),B(2,-3) are two points.The equation to the locus of P. such that PA+PB=8

A point P(x,y,z) is such that 3PA=2PB where AandB are the point (1,3,4) and (1,-2,-1), irrespectivley. Find the equation to the locus of the point P and verify that the locus is a sphere.

Given the points A(0,4) and B(0,4). Then the equation of the locus of the point P(x,y) such that |AP-BP|=6, is

If A(3,0), B(-3,0) and PA+PB=10 then the equation of the locus of P is

B and C are fixed points having co-ordinates (3,0) and (-3,0) respectively.If the vertical angle BAC is 90^(@), then the locus of the centroid of the Delta ABC has the equation

A and B are two given points whose coordinates are (-5, 3) and (2, 4) respectively. A point P moves in such a manner that PA : PB = 3:2 . Find the equation to the locus traed out by P .

The coordinates of the point A and B are (a,0) and (-a,0), respectively.If a point P moves so that PA^(2)-PB^(2)=2k^(2), when k is constant,then find the equation to the locus of the point P.