Home
Class 11
MATHS
In the hyperbola 16x^(2) - 9y^(2) = 144....

In the hyperbola `16x^(2) - 9y^(2) = 144`. Find the equation to the diameter which is conjugate to the diameter whose equation is x = 2y.

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

If the equation to the hyperbola is 3x^(2)-5xy-2y^(2)+5x+11y-8=0 then equation to the conjugate hyperbola is

For the ellipse,(x^(2))/(a^(2))+(y^(2))/(b^(2))=1 the equation of the diameter conjugate ax-by=0 is-

The diameter of 16x^(2)-9y^(2)=144 which is conjugate to x=2y is

y=2x be a chord of the circle x^(2) +y^(2)=10x . Find the equation of a circle whose diameter is this chord.

If the equation of the diameter AB is x = y then the equation of the conjugate diameter CD will be

Find the equation of that diameter which bisects the chord 7x+y-2=0 of the hyperbola (x^(2))/(3)-(y^(2))/(7)=1 .