`n_(1)` mole of a monoatomic gas is mixed with `n_(2)` mole of diatomic gas such that `gamma_( mixture )`=`1.5` .Then

When 1 mole of monoatomic gas is mixed with 2 moles of diatomic gas, then find gamma for the mixture of gases.

n_1 mole of a monoatomic gas is mixed with n_2 mole of a diatomic gas. (Assume gases are ideal). If for the mixture adiabatic contant is found to be 1.5, then n_1 : n_2 is :

When one mole of monoatomic gas is mixed with one mole of triatomic gas, then the equivalent value of gamma for the mixture will be (vibration mode neglected)

One mole of a monoatomic gas is mixed with 3 moles of a diatomic gas. The molecular specific heat of the mixture at constant pressure is (13)/(8)xxKxxR . Then find the value of K .

One moles of a monatomic gas is mixed with three moles of a diatomic gas. The molar specific heat of the mixture at constant volume is

If one mole of a monatomic gas (gamma=5/3) is mixed with one mole of a diatomic gas (gamma=7/5), the value of gamma for mixture is

If one mole of a monatomic gas (gamma=5/3) is mixed with one mole of a diatomic gas (gamma=7/5), the value of gamma for mixture is

One mole of a mono-atomic ideal gas is mixed with one mole of a diatomic ideal gas. The molar specific heat of the mixture at constant volume is ……

One mole of ideal monoatomic gas (gamma=5//3) is mixed with one mole of diatomic gas (gamma=7//5) . What is gamma for the mixture? gamma Denotes the ratio of specific heat at constant pressure, to that at constant volume

When 1 mole of monatomic gas is mixed 1 mole of diatomic gas, then find C_(p),C_(v),gamma and f for mixture of the gas.