At `27^o` C a gas is suddenly compressed such that its pressure becomes 1/32 times of original pressure. the temperature of the gas will be(`gamma` = 5/3)

300K a gas (gamma = 5//3) is compressed adiabatically so that its pressure becomes 1//8 of the original pressure. The final temperature of the gas is :

When a gas is suddenly compressed, its temperature rises. Why?

An ideal gas at a pressure of 1 atm and temperature of 27^(@)C is compressed adiabatically until its pressure becomes 8 times the initial pressure , then final temperature is (gamma=(3)/(2))

An ideal gs at pressure P is adiabatically compressed so that its density becomes n times the initial vlaue The final pressure of the gas will be (gamma=(C_(P))/(C_(V)))

A gas is compressed adiabatically till its pressure becomes 27 times its initial pressure. Calculate final temperature if initial temperature is 27^@ C and value of gamma is 3/2.

A gas is suddenly compressed to 1/4th of its original volume. Caculate the rise in temperature when original temperature is 27^(@)C. gamma= 1.5 .

An ideal gas is found to obey the law V^2T = constant . The initial pressure and temperature are P_0 and T_0 . If gas expands such that its pressure becomes (P_0)/4 , then the final temperature of the gas will be

400 c c volume of gas having gamma=5/2 is suddenly compressed to 100 c c . If the initial pressure is P , the final pressure will be

A fixed mass of an ideal gas is compressed in such a manner that its pressure and volume can be related as P^3V^3 = constant. During this process, temperature of the gas is.

A gas in a vessel is heated in such a way that its pressure and volume both becomes two times. The temperature of the gas expressed in Kelvin scale becomes