A person covers half a round of a circular track of radius `R`. The displacement and distance covered by the person are:
(1) `R` and 2`pi``R`
(2) 2`pi``R` and `R`
(3) `pi``R` and 2`R`
(4) 2`R` and `pi``R`

A particle in a circular motion covers a distance of 0.5 pi r where r is the radius of the circular path. What is the angular displacement ?

The area of the curved surface of a cone of radius 2r and slant height l/2 is a) pirl b) 2pirl c) 1/2 pir l d) pi(r+l)r

The area of a circular path of uniform width h surrounding a circular region of radius r is (A) pi (h+2r)r (B) pi h(2r+h)dot (C) pi (h+r) r (D) pi (h+r) h

The area of a circle is given by A= pi r^(2) , where r is the radius. Calculate the rate of increase of area w.r.t radius.

Figure shows a sector of a circle of radius r containing an angle theta^@ The area of the sector is A cm^2 and the perimeter is 50cm. Prove that theta = (360)/pi ((25)/r-1) and A=25r -r^2

Which of the following expresses the circumference of a circle inscribed in a sector O A B with radius Ra n dA B=2a ? (a) 2pi(R a)/(R+a) (b) (2piR^2)/a (c) 2pi(r-a)^2 (d) 2piR/(R-a)

The specific resistance rho of a circular wire of radius r , resistance R , and length l is given by rho = pi r^(2) R//l . Given : r = 0.24 +- 0.02 cm , R = 30 +- 1 Omega , and l = 4.80 +- 0.01 cm . The percentage error in rho is nearly

In triangle ABC, let angle C = pi//2 . If r is the inradius and R is circumradius of the triangle, then 2(r + R) is equal to

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle (a) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (c) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)