A half ring of radius r has a linear charge density `lamda` .The potential at the centre of the ring is `lamda``//`p `epsilon 0` Then the value of 'p' is
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A half ring of radius r has a linear charge density lambda .The potential at the centre of the half ring is

A ring of radius 3 m has charge density lambda . Electric potential at 4 m from its centre on its axis is ____ [k=(1)/(4pi epsilon_(0))]

An infinite cylinder of radius r_(o), carrying linear charge density lamda. The equation of the equipotential surface for the cylinder is

A particle of mass m and charge -Q is constrained to move along the axis of a ring of radius a. The ring carries a uniform charge density +lamda along its length. Initially, the particle is in the centre of the ring where the force on it is zero. Show that the period of oscillation of the particle when it is displaced slightly from its equilibrium position is given by T=2pisqsqrt((2epsilon_0ma^2)/(lamdaQ))

Charge q is uniformly distributed over a thin half ring of radius R . The electric field at the centre of the ring is

A circular ring of radius R and uniform linear charge density +lamdaC//m are kept in x - y plane with its centre at the origin. The electric field at a point (0,0,R/sqrt(2)) is

A thin circular wire of radius r has a charge Q. If a point charge q is placed at the centre of the ring, then find the increase in tension in the wire.

A ring of radius R having a linear charge density lambda moves towards a solid imaginary sphere of radius (R)/(2) , so that the centre of ring passes through the centre of sphere. The axis of the ring is perpendicular to the line joining the centres of the ring and the sphere. The maximum flux through the sphere in this process is

There is a ring of radius r having linear charge density lambda and rotating with a uniform angular velocity omega. the magnetic field produced by this ring at its own centre would be

A ring of radius R carries a non - uniform charge of linear density lambda = lambda_(0)costheta sec in the figure) Magnitude of the net dipolement of the ring is :