If `cos theta=(x)/(2)` Then find `sin((theta)/(2))`

cos2 theta*cos(theta/(2))-cos3 theta*cos((9theta)/2)=sin5 theta*sin((5theta)/(2))

If cos theta = (2x)/(1+x^2) , find the values of sin theta and cot theta [Given x^2 lt 1 ]

If cot theta = (x)/(y) , find the value of: " " ( x cos theta + y sin theta)/( y sin theta - x cos theta)

If (cos theta_(1))/(cos theta_(2))+(sin theta_(1))/(sin theta_(2))=(cos theta_(0))/(cos theta_(2))+(sin theta_(0))/(sin theta_(2))=1 , where theta_(1) and theta_(0) do not differ by can even multiple of pi , prove that (cos theta_(1)*cos theta_(0))/(cos^( 2)theta_(2))+(sin theta_(1)*sin theta_(0))/(sin^(2) theta_(2))=-1

Find the A.M. between: ( cos theta + sin theta )^(2) and ( cos theta - sin theta)^(2)

The roots of the equation |(3x^(2),x^(2) + x cos theta + cos^(2) theta ,x^(2) + x sin theta + sin^(2) theta),(x^(2) + x cos theta + cos^(2) theta,3 cos^(2) theta,1 + (sin 2 theta)/(2)),(x^(2) + x sin theta + sin^(2) theta,1 + (sin 2 theta)/(2),3 sin^(2) theta)| = 0

Evaluate : int (2 sin 2 theta- cos theta)/(6 - cos^(2) theta- 4 sin theta) d theta

Statement I If 2 cos theta + sin theta=1(theta != (pi)/(2)) then the value of 7 cos theta + 6 sin theta is 2. Statement II If cos 2theta-sin theta=1/2, 0 lt theta lt pi/2 , then sin theta+cos 6 theta = 0 .

1 + (cos 2 theta + cos 6 theta)/(cos 4 theta) = (sin 3 theta)/(sin theta).

If "cosec" theta = sqrt(5) , find the value of (i) 2-sin^(2)theta - cos^(2)theta (ii) 2 + (1)/(sin^(2)theta) - (cos^(2)theta)/(sin^(2)theta)