Charge in terms of Faraday is required to reduce one mol of `MnO_(4)^(-)` to `Mn^(+2)`.
`3F`
`4F`
`5F`
`6F`

Number of Faradays required to reduce 3 mol of MnO_(4)^(c-) to Mn^(2+) is ……………………….F

How many Faradays are needed to reduce 1 mole of MnO_(4)^(-) to Mn^(2+) ?

The charge required for reducing 1 mole of MnO_4^(-) to Mn^(2+) is

The quantity of electricity required to reduce 0.5 mole of (MnO_(4))^(1-) to Mn^(2+) is

In acidic medium is converted to Mn2+. The quantity of electricity in faraday required to reduce 0.5 mole MnO_(4)^(-) to Mn^(2+) would be :

How many coulombs are required for the following reductions? 1 mol of MnO_(4)^(-) " to "Mn^(2+) .

The quantity of electricity requried to reduce 0.05 mol of MnO_(4)^(-) to Mn^(2+) in acidic medium would be

How many faradays of charge are required to convert: (a). 1 mole of MnO_(4)^(-) to Mn^(2+) ion, (b). 1 mole of Cr_(2)O_(7)^(2-) to Cr^(2+) ion

How many Faradays are required to reduce 1 mol of BrO_(3)^(c-) to Br^(c-) in basic medium ? 1) 6 2) 5 3) 4 4) 3

How many Faradays of electricity are required for the given reaction to occur? MnO_(4)^(-) rarr Mn^(2+)