If k = `( 1 + tan^2theta )` + `[ 1 + ( tan^2theta )^(-1 ) ]` then simplify k

(1+tan^(2)theta)/(1-tan^(2)theta) =

(1+tan^(2)theta)/(1-tan^(2)theta) =

Simplify (1 + tan ^(2) theta ) ( 1 + sin theta ) ( 1 - sin theta )

If (1+tan^2 theta)+(1+ (tan^2 theta)^-1)=k , then sqrtk =? यदि (1+tan^2 theta)+(1+ (tan^2 theta)^-1)=k ,है, तो sqrtk =?

Prove that : (1 - tan^(2) theta)/(1 + tan^(2) theta) = cos^(2) theta - sin^(2) theta

tan2 theta tan theta=1

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=