If 4g of NaOH dissolves in 100g/cc of `H_(2)O` ,determine the molality of solutions

4 g of NaOH are dissolved in 200 cm^3 of water. Find the molarity of the solution.

If 4 g of NaOH dissovles in 36g of H_(2)O , calculate the mole fraction of each component in the solution. Also determine the molarity of the solution (specific gravity of solution is 1g mL^(-1) ).

8g of NaOH is dissolved in 18g of H_(2)O . Mole fraction of NaOH in solution and molality (in mol kg^(-1) ) of the solutions respectively are:

8g of NaOH is dissolved in 18g of H_(2)O . Mole fraction of NaOH in solution and molality (in mol kg^(-1) ) of the solutions respectively are:

4.0g of substance A dissolved in 100g H_(2)O depressed the freezing point of water by 0.1^(@)C while 4.0g of another substance B depressed the freezing point by 0.2^(@)C . Which one has higher molecular mass and what is the relation ?

A solution is made by dissolving 49g of H_2SO_4 in 250 mL of water. The molarity of the solution prepared is

At 0^@C , the vapour pressure of pure water is 4.63 mm and an aqueous solution of 8.49 g of NaNO_3 dissolved in 100g of water is 4.483 mm. What is the extent of ionisation of NaNO_3 /

171 g of cane sugar (C_(12) H_(22) O_(11)) is dissolved in 1 litre of water. The molarity of the solution is

8g NaOH is dissolved in one litre of solution, its molarity is

0.1 mole of sugar is dissolved in 250 g of water. The freezing point of the solution is [K_(f) "for" H_(2)O = 1.86^(@)C "molal"^(-1)]