If breakdown voltage of each capacitor is 50V then find the maximum emf of the battery so that no capacitor will fuse :-

(1) 70Volt

(2) 50Volt

(3) 60Volt

(4) 35Volt

If charge on 5 muF capacitor is 50 muC , then find the potential difference on 4 muF and emf of battery.

Area of each plate is A . The conducting plates are connected to a battery of emf V volts. Find charges q_1 to q_t .

The work done in increasing the potential of a capacitor from V volt to 2V volt is W Then, the work done in increasing the potential of the same capacitor from 2V volt to 4V volt will be.

If there are n capacitors in parallel connected to V volt source, then the energy stored is equal to

Find the maximum value of current when inductance of two henry is connected to 150 volt, 50 cycle supply.

In the figure an A.C of rms voltage 200 volt is appled to the circuit containing diode and the capacitor and it is being rectified. The maximum potential across the capacitor C in volt will be

A parallel plate capacitor 'A' of capacitance 1 muF is charged to a potential drop 100 volt and then disconnected form the battery. Now the capacitor 'A' is completely filled with a dielectric slap of dielectric constant k = 4 . Another parallel plate capacitor 'B' of capacitance 2 muF is charged to a potential drop 20 volt and then disconnected from the battery. Now the two capacitors 'A' and 'B' are connected with each other with opposite polarities. Then the heat dissipated after connecting the capacitors is

Two capacitros are fully charged by a battery as shown in the figure. If the capacitors are disconnected from battery and plate 1 is connected to plate 4 & plate 2 to plate 3, then find the potential difference (in volts) across capacitors finally.

A parallel plate capacitor is connected to a battery of emf V volts. Now a slab of dielectric constant k=2 is inserted between the plates of capacitor without disconnecting the battery. The electric field between the plates of capacitor after inserting the slab is E= (PV)/(2d) . Find the value of P.

The area of the plates of a capacitor is 50cm^(2) each and the separation between them is 1mm. The space between the plates is filled with a material of dielectric constant 4. the capacitor, initially uncharged, is connected to a battery of EMF 50 V. the work done by the battery until the capacitor gets completely charged is (in muJ ).