dhoran 6 samajik vigyan path 16 swadhyay || std 6 social scince ch.16 sthanik sarkar swadhyay,ધોરણ 6 સામાજિક વિજ્ઞાન પાઠ 16 સ્થાનિક સરકાર

In young,s double slit experience monochromatic light, the frings pattern shifts by a certain distance on the screen when a mica sheet of refractive index 1.6 and thickness 1.964 microns is introduced in the path of one of the interfering waves. The mica sheet is then sheet is then removed and the distance between the slits and the screen is doubled. It is found that now the distance between succesive maximum (or minimum) is the same as the observed fringe-shift upon the introduction o fthe mica sheet. Calculate the wavelength of the monochromatic light used in the experiment.

In a Young's double slit experiment using monochromatic light, the fringe pattern shifts by a certain distance on the screen when a mica sheet of refractive index 1.6 and thickness 1.964 microns is introduced in the path of one of the interfering waves. The mica sheet is then removed and the distance between the slits and screen is doubled. It is found that the distance between successive maxima now is the same as observed fringe shift upon the introduced of the mica sheet . Calculate the wavelength of the monochromatic light used in the experiment .

In YDSE using monochromatic light the fringe pattern shifts by a certain distance on the screen when a mica sheet of refractive index 1.6 and thickness 1.964 microns is introduced in the path of one of the interfering waves. The mica sheet is then removed and the distance between the plane of slits and the screen is doubled. It is found that the distance between successive maxima (or minima) now is the same as the observed fringe shift upon the introduction of the mica sheet. Calculate the wavelength of the light.

The number of electrons in 1.6 g of CH_(4) is approximately

In a bank, there are as many coins as the number of molecules in 1.6 mug of CH_(4) . How many coins are there in the bank ?

Assertion (A) : If the outer and inner diameter of a circular path is 10 m and 6 m then area of the path is 16 pi m^(2) Reason (R) : If R and r be the radius of outer and inner circular path . Area of circular path = pi (R^(2) - r^(2))

When light of wavelangth 4000 Å is incident on a barium emitter , emitted photo electrons in a transverse magnetic field strength B = 5.2 xx 10^(-6) T moves in a circular path . Find the radius of the circle . Given work function of barium is 2.5 eV and mass of electron is 9.1 xx 10^(-31) kg . e = 1.6 xx 10^(-19) C , h = 6.6 xx 10^(34) Js .