A particle is projected vertically upward to its maximum height H. Find out the height from the ground when its velocity is half of its maximum velocity :-

A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time t (lt T) will be

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A body is projected vertically up with u. Its velocity at half its maximum height is

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?

A particle is projected vertically upwards the surface of the earth (radius R_(e)) with a speed equal to one fourth of escape velocity what is the maximum height attained by it from the surface of the earth?

A body is thrown vertically up with certain velocity. If h is the maximum height reached by it, its position when its velocity reduces to 1/3 of its velocity of projection is at

A ball is projected vertically upward with speed of 50 m/s. Find a. the maximum height, b. the time to reach the maximum height, c. the speed at half the maximum height. Take g= 10 m/s^2 .

A particle is projected vertically upwards from ground. Which of the following plots best describe the momentum vs height from the ground?

A particle is projected vertically upwards. Prove that it will be at three-fourth of its greatest height at times which are in the ratio 1: 3 .

A stone is dropped from the top of a tower of height h=60m. Simultaneously another stone is projected vertically upwards from the foot of the tower. They meet at a height (2h)/3 from the ground level. The initial velocity of the stone projected upwards is (g=10ms^(-2))