The displacements of two interfering sound waves are `Y_1 = 4 sin(wt)` and `Y_2 = 3 sin(wt+(pi/2))` . what is the amplitude of the resultant wave

The displacement of two interfering light waves are y_(1)=4 sin omega t" and "y_(2)= 3 cos (omega t) . The amplitude of the resultant waves is (y_(1)" and "y_(2) are in CGS system)

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

two waves y_1 = 10sin(omegat - Kx) m and y_2 = 5sin(omegat - Kx + π/3) m are superimposed. the amplitude of resultant wave is

If two waves represented by y1=4sinῳt and y2= 3sin(ῳt+π/4) interfere at apoint.Find out the amplitude of the resulting wave .

If two waves represented by y_(1)=4sinomegat and y_(2)=3sin(omegat+(pi)/(3)) interfere at a point find out the amplitude of the resulting wave

The displacement at a point due to two waves are y_1=4 sin (500pit) and y_2=2sin(506 pi t) . The result due to their superposition will be

Two waves represented by y=a" "sin(omegat-kx) and y=a" " sin(omega-kx+(2pi)/(3)) are superposed. What will be the amplitude of the resultant wave?

Two waves represented by y=a" "sin(omegat-kx) and y=a" " sin(omegat-kx+(2pi)/(3)) are superposed. What will be the amplitude of the resultant wave?

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .