In Young's double slit interference, experiment,the slit widths are in the ratio, 1:25.Then the ratio of intensity at the, maxima and minima in the interference , pattern is

Two slits in Youngs experiment have widths in the ratio 1: 25.h The ratio of intensity at the macxima and minima in the interderence pattern I_(max)/(I_(min))is is

In Young's double slit experiment, if the slit widths are in the ratio 1:9 , then the ratio of the intensity at minima to that at maxima will be

In Young's double slit experiment, if the slit widths are in the ratio 1:9 , then the ratio of the intensity at minima to that at maxima will be

In an interference pattern, the slit widths are in the ratio 1 : 9 . Then find out the ratio of minimum and maximum intensity.

In Young's interference experiment, if the slit are of unequal width, then

In Young's interference experiment, if the slit are of unequal width, then

In an intereference pattern ,the slit widths are in the ratio 1:16 .then find out the ratio of minimum and maxima intensity.

In Young'double-slit interference experiment, if the slit separation is made threefold, the fringe width becomes

In a Young’s double slit experiment, the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be:

If the intensity of light in double slit experiment from slit 1 and slit 2 are l_(0) and 25l_(0) respectively, find the ratio of intensities of light at minima and maxima in the interference pattern.