Home
Class 12
CHEMISTRY
H(2)SO(4) oxidizes glucose (C(6)H(12)O(6...

`H_(2)SO_(4)` oxidizes glucose `(C_(6)H_(12)O_(6))` to `CO_(2)` according to the equation
`C_(6)H_(12)O_(6)+H_(2)SO_(4)rightarrow CO_(2)+SO_(2)+H_(2)O`
Number of electrons lost by `225` grams glucose in the reaction are nearly

Promotional Banner

Similar Questions

Explore conceptually related problems

The oxidation number of C in glucose (C_(6)H_(12)O_(6)) is

360 amu of Glucose (C_6H_12O_6) contains :

Na_(2)C_(2)O_(4)+H_(2)SO_(4)(Conc.) to Na_(2)SO_(4)+CO+CO_(2)

Na_(2)C_(2)O_(4)+H_(2)SO_(4)(Conc.) to Na_(2)SO_(4)+CO+CO_(2)

Balance the following equation: C+H_(2)SO_(4)toCO_(2)+H_(2)O+SO_(2)

Balance the following equation : Kl + H_(2)SO_(4) + H_(2)O_(2) to K_(2)SO_(4) + I_(2) + H_(2)O

The reaction, C_(6)H_(5)ONa +CO_(2)+H_(2)O rarr C_(6)H_(5)OH+NaHCO_(3) suggests that :

H_(2)underline(S_(2))O_(8)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)

H_(2)underline(S_(2))O_(8)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)

H_(2)underline(S)O_(5)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)