Molality of an aqueous solution that produces an elevation of boiling point of 1.00K at 1 atm pressure.`(K_(b) ` for water =`0.512K*kg*mol^(-1))`

Calculate the molar mass of a substance 1 g of which when dissolved in 100 g of water gave a solution boiling at 100.1^(@)C at a pressure of 1 atm (K_(b) for water = 0.52 K kg mol^(-1))

0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

3.0 molal aqueous solution of an electrolyte A_(2)B_(3) is 50% ionised. The boilng point of the solution at 1 atm is: [k_(b) (H_2O) = 0.52 K kg mol^(-1)]

Calculate the b.pt. of 1 molar aqueous solution of KBr. Given that the density of solution is 1.06 gmL^(-),K_(b) , for water is 0.52 K kg "mol"^(-) [Atomic mass of K = 39. Br=80]

A solution containg 12 g of a non-electrolyte substance in 52 g of water gave boiling point elevation of 0.40 K . Calculate the molar mass of the substance. (K_(b) for water = 0.52 K kg mol^(-1))

A solution of an organic compound is prepared by dissolving 30 g in 100 g water. Calculate the molecular mass of compound and the osmotic pressure of solution at 300 K , when the elevation in boiling point is 0.52 and K_(b) for water is 0.52 K m^(-1) .

A 1.00 molal aqueous solution of trichloroacetic acid (CCl_(3)COOH) is heated to its boiling point. The solution has the boiling point of 100.18^(@)C . Determine the van't Hoff factor for trichloroacetic acid. ( K_(b) for water =0.512K kg "mol"^(-1) )

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The boiling point of the solution is (K_(b) for H_(2)O = 0.52 K kg//mol) :

Calculate the freezing point depression and boiling point elevation of a solution of 10.0 g of urea (M_(B)=60) in 50.0 g of water at 1 atm . pressure. K_(b) and K_(f) for water 0.52^(@)C m^(-1) and 1.86^(@)C m^(-1) respectively.