Three capacitors each of 4 `mu` F are to be connected in series and parallel in such a way that the effective capacitance is 6 `mu` F.If P number of capacitors are connected in series with Q number of capacitor in parallel,then the value of (2P+Q) is

Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF . This can be done by

Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF . This can be done by

Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF . This can be done by

Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

Two capacitors of capacitance C are connected in series. If one of them is filled with dielectric substance K, what is the effective capacitance?

Three capacitor of capacitance C(mu F) are connected in parallel to which a capacitor of capacitance C is connected in series. Effective capacitance is 3.75. then capacity off each capacitor is

Four capacitors are connected as shown in the figure. The equivalent capacitance between P and Q is

Two capacitors of 2mu F and 3mu F are connected in series. The potential at point A is 1000 volt and the outer plate of 3mu F capacitor is earthed. The potential at point B is

Three capacitors each of capacitance C are connected in series. Their equivalent capacitance is C_(s) . The same three capacitors are now connected in parallel. Their equivalent capacitance becomes C_(p) . Find the ratio ((C_(p))/(C_(s))) (Working must be shown).

Effective capacitance of parallel combination of two capacitors C_(1) and C_(2) is 10muF . When the capacitors are individually connected to a voltage source of 1V, the energy stored in the capacitor C_(2) is 4 times of C_(1) . If these capacitors are connected in series, their effective capacitor will be: lt