If density of vapours of a substance of molar mass 18gm/mole at 1 atm pressure and 500K is `0.36kgm^(-3)` then value of (Z) compressibility factor for the vapour is [Take R=0.082 L atm `mol^(-1)` `k^(-1)`]

The density of vapours of a substance of molar mass 18 g at 1 atm pressure and 500 K is 0.36 kg m^(-3) . The value of compressibility factor Z for the vapours will be (Take R = 0.082 L atm mol ^(-1) K^(-1)

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

The density of vapours of a substance at 1 atm and 500 K is 0.3 kg m^(-3) . The vapours effuse 0.4216 times faster than O_(2) through a pin hole under identical conditions. If R= 0.08 litre atm K^(-1) mol^(-1) . The molar volume of gas is a xx 10^(2) litre. The value of a is _____________.

The density of the vapour of a substance at 1 atm pressure and 500 K is 0.36 kg m^(-3) . The vapour effuses through a small hole at a rate of 1.33 times faster than oxygen under the same condition. ( a ) Determine ( i ) the molecular weight, ( ii ) the molar volume

The density of the vapour of a substance at 1 atm pressure and 500 K is 0.36 kg m^(-3) . The vapour effuses through a small hole at a rate of 1.33 times faster than oxygen under the same condition. ( a ) Determine ( i ) the molecular weight, ( ii ) the molar volume

The density of the vapour of a substance at 1 atm pressure and 500 K is 0.36 kg m^(-3) . The vapour effuses through a small hole at a rate of 1.33 times faster than oxygen under the same condition. If the vapour behaves ideally at 1000 K, determine the average translational kinetic energy of a molecule.

The density of the vapour of a substance at 1 atm pressure and 500 K is 0.36 kg m^(-3) . The vapour effuses through a small hole at a rate of 1.33 times faster than oxygen under the same condition. Determine, (a) molecular weight (b) molar volume (c) compression factor (Z) of the vapour and (d) which forces among the gas molecules are dominating, the attractive or the repulsive?

The density of vapour of a substance (X) at 1 atm pressure and 500 K is 0.8 kg//m^(3) . The vapour effuse through a small hole at a rate of 4//5 times slower than oxygen under the same condition. What is the compressibility factor (z) of the vapour ?

The volume of 2.8g of CO at 27^(@)C and 0.821 atm pressure is (R=0.0821 lit. atm mol^(-1)K^(-1))

The vapour of a substance effuses through a small hole at the rate 1.3 times faster than SO_(2) gas at 1 atm pressure and 500 K. The molecular weight of the gas is